![]() Multi-line flag m (this is specified in various ways in various languages/contexts) /^CTR. There could be a whole discussion on the best strategy for picking lines out of a file to process them, and some of the strategies would require this: ![]() Note: Depending on how and where you're using regex, you might have to use a multi-line modifier to get it to match multiple lines. If you want to get crazy, use the end of line matcher $Īdd that to the growing regex pattern: ^CTR.*$ However, if you need to get the text from the whole line in your language of choice, add a "match anything" pattern. Solution 3 Regex symbol to match at beginning of a line: ^Īdd the string you're searching for ( CTR) to the regex like this: ^CTR *$ or whatever, depending on what language/regex function you are using. Note: This character has a different meaning when it appears at the start of a character class. For example, /A/ does not match the 'A' in 'an A', but does match the first 'A' in 'An A'. But if you are trying to match and grab the line, you will need something like. If the multiline flag is set to true, also matches immediately after a line break character. I don't know, what language are you are using. But if this is the case, you may be better off using a prefab substr() type function. If all you want to do is match for a line itself (and already have the line to use), then that is all you really need. To be more clear: ^CTR will match start of line and those chars. So to run \r\nCTR.* you would use it as "\\r Note, if you are going to use the backslash \ in some program string that supports escaping, like the php double quotation marks "" then you need to escape them first \r = carriage return / old Mac OS newline While in multi-line mode you can still match the start and end of the string with \A\Z permanent anchors /\ACTR.*\Z/mĪs such, another way to match the start of the line would be like this: /(\A|\r|\n|\r\n)CTR.*/ M = enables multi-line mode, this sets regex to treat every line as a string, so ^ and $ will match start and end of line * = zero or more of any character except newline * = zero or more of any character except newline Start and end of line /^CTR.*$/m z replaces every character in the region iteratively by z. edit: (query-replace-regexp '\.' 'z' nil b e) doesn't work, and M-x query-replace-regexp \.![]() This is difficult then only the broader match itself is visible. Beginning of line or beginning of string? Start and end of string /^CTR.*$/ I need to see the surrounding context when deciding whether or not to replace a match in my RL case.
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